tomcat下如何才能运行shtml文件？
2009-04-29 16:35:31 来源：WEB开发网 闂侀潧妫撮幏锟�
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我们知道，需要运行shtml，必须在web服务器上配置好ssi。
下面是ssi在tomcat5.*上的配置方法：
打开tomcat配置文件：conf/web.xml：
1、去掉下面servlet前的注释
/* <servlet>
<servlet-name>ssi</servlet-name>
<servlet-class>
org.apache.catalina.ssi.SSIServlet
</servlet-class>
<init-param>
<param-name>buffered</param-name>
<param-value>1</param-value>
</init-param>
<init-param>
<param-name>debug</param-name>
<param-value>0</param-value>
</init-param>
<init-param>
<param-name>expires</param-name>
<param-value>666</param-value>
</init-param>
<init-param>
<param-name>isVirtualWebapPRelative</param-name>
<param-value>0</param-value>
</init-param>
<load-on-startup>4</load-on-startup>
</servlet>
*/
改成
<servlet>
<servlet-name>ssi</servlet-name>
<servlet-class>
org.apache.catalina.ssi.SSIServlet
</servlet-class>
<init-param>
<param-name>buffered</param-name>
<param-value>1</param-value>
</init-param>
<init-param>
<param-name>debug</param-name>
<param-value>0</param-value>
</init-param>
<init-param>
<param-name>expires</param-name>
<param-value>666</param-value>
</init-param>
<init-param>
<param-name>isVirtualWebappRelative</param-name>
<param-value>0</param-value>
</init-param>
<load-on-startup>4</load-on-startup>
</servlet>
2、去掉servlet映射的注释
/*<servlet-mapping>
<servlet-name>ssi</servlet-name>
<url-pattern>*.shtml</url-pattern>
</servlet-mapping>
*/
改成
<servlet-mapping>
<servlet-name>ssi</servlet-name>
<url-pattern>*.shtml</url-pattern>
</servlet-mapping>
3、在server\lib目录中找到servlets-ssi.renametojar文件，改成 servlets-ssi.jar
4、重启tomcat
5、新建一个shtml文件测试一下
<HTML>
<HEAD>
<TITLE>shtml测试</TITLE>
</HEAD>
<BODY>
<!–#echo var=”DATE_LOCAL” –>
<!–#include virtual=”hello.jsp”–>
</BODY>
</HTML>
执行ok！！！
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