用Java编写扫雷游戏--代码思想
2008-01-05 09:40:17 来源:WEB开发网核心提示:import java.awt.*; import java.awt.event.*; import javax.swing.*;/*按扭类*/class Bomb extends JButton { public int num_x,num_y; //第几号方块 public int BombRo
import java.awt.*;
import java.awt.event.*;
import javax.swing.*;
/*按扭类*/
class Bomb extends JButton
{
public int num_x,num_y; //第几号方块
public int BombRoundCount; //四周雷数
public boolean isBomb; //是否为雷
public boolean isClicked; //是否被点击
public int BombFlag; //探雷标记
public boolean isRight; //是否点击右键
public Bomb(int x,int y)
{
BombFlag = 0;
num_x = x;
num_y = y;
BombRoundCount = 0;
isBomb = false;
isClicked = false;
isRight = false;
}
}
/*窗口及算法实现类*/
class MainBomb extends JFrame implements ActionListener,MouseListener
{
public JTextField text;
public Label nowBomb,setBomb;
public int BlockNum,BombNum; //当前方块数当前雷数
public Icon icon_bomb = new ImageIcon("Bomb.gif"); //踩雷
public Icon icon_bomb_big = new ImageIcon("bomb_big.gif"); //踩雷标记
public Icon icon_flag = new ImageIcon("flag.gif"); //雷标记
public Icon icon_question = new ImageIcon("question.gif"); //迷惑是否有雷
public JButton start = new JButton(" 开始 ");
public Panel MenuPamel = new Panel();
public Panel mainPanel = new Panel();
public Bomb[][] bombButton;
/*界面设计*/
public MainBomb()
{
super("扫雷 Aaron2004制作 2004.8 ");
BlockNum = 64;
BombNum = 10;
Container c=getContentPane();
c.setBackground(Color.gray);
c.setLayout(new BorderLayout());
text=new JTextField("10 ",3);
nowBomb = new Label("当前雷数"+" "+BombNum+"");
setBomb= new Label("设置地雷数");
start.addActionListener(new ActionListener(){
public void actionPerformed(ActionEvent e)
{
BombNum = Integer.parseInt(text.getText().trim());
if(BombNum >= 10 && BombNum < 50 )
replay();
else
{
JOptionPane msg = new JOptionPane();
JOptionPane.showMessageDialog(null,"您设置的地雷数太多了,请重设!","错误",2);
}
}
} );
MenuPamel.add(setBomb);
MenuPamel.add(text);
MenuPamel.add(start);
MenuPamel.add(nowBomb);
c.add(MenuPamel,"North");
mainPanel.setLayout(new GridLayout( (int)Math.sqrt(BlockNum) , (int)Math.sqrt(BlockNum)) );
bombButton=new Bomb[ (int)Math.sqrt(BlockNum) ][];
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