Java String 的 equals() 方法可能的优化
2008-01-05 19:11:05 来源:WEB开发网核心提示:JDK1.4, 1.5 的 String Class 代码如下 以下内容为程序代码public final class String implements java.io.Serializable, Comparable<String>, CharSequence{ /** The value is u
JDK1.4, 1.5 的 String Class 代码如下
以下内容为程序代码
public final class String
implements java.io.Serializable, Comparable<String>, CharSequence
{
/** The value is used for character storage. */
PRivate final char value[];
/** The offset is the first index of the storage that is used. */
private final int offset;
/** The count is the number of characters in the String. */
private final int count;
以下内容为程序代码
/**
* Initializes a newly created <code>String</code> object so that it
* represents the same sequence of characters as the argument; in other
* Words, the newly created string is a copy of the argument string. Unless
* an eXPlicit copy of <code>original</code> is needed, use of this
* constrUCtor is unnecessary since Strings are immutable.
*
* @param original a <code>String</code>.
*/
public String(String original) {
int size = original.count;
char[] originalValue = original.value;
char[] v;
if (originalValue.length > size) {
// The array representing the String is bigger than the new
// String itself. Perhaps this constructor is being called
// in order to trim the baggage, so make a copy of the array.
v = new char[size];
System.arraycopy(originalValue, original.offset, v, 0, size);
} else {
// The array representing the String is the same
// size as the String, so no point in making a copy.
v = originalValue;
}
this.offset = 0;
this.count = size;
this.value = v;
}
从这段构造函数中,我们可以看出,不同Reference的String之间有可能共享相同的 char[]。
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