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MSSQL处理表重复记录

 2012-10-29 13:44:13 来源:WEB开发网   
核心提示: --处理表重复记录(查询和删除)1、Num、Name相同的重复值记录,没有大小关系只保留一条2、Name相同,ID有大小关系时,保留大或小其中一个记录--1、用于查询重复处理记录(如果列没有大小关系时2000用生成自增列和临时表处理,SQL2005用row_number函数处理)if not object_id(&#

 --处理表重复记录(查询和删除)
1、Num、Name相同的重复值记录,没有大小关系只保留一条
2、Name相同,ID有大小关系时,保留大或小其中一个记录


--1、用于查询重复处理记录(如果列没有大小关系时2000用生成自增列和临时表处理,SQL2005用row_number函数处理)


if not object_id('Tempdb..#T') is null
drop table #T
Go
Create table #T([ID] int,[Name] nvarchar(1),[Memo] nvarchar(2))
Insert #T
select 1,N'A',N'A1' union all
select 2,N'A',N'A2' union all
select 3,N'A',N'A3' union all
select 4,N'B',N'B1' union all
select 5,N'B',N'B2'
Go


--I、Name相同ID最小的记录(推荐用1,2,3),方法3在SQl05时,效率高于1、2
方法1:
Select * from #T a where not exists(select 1 from #T where Name=a.Name and ID<a.ID)


方法2:
select a.* from #T a join (select min(ID)ID,Name from #T group by Name) b on a.Name=b.Name and a.ID=b.ID


方法3:
select * from #T a where ID=(select min(ID) from #T where Name=a.Name)


方法4:
select a.* from #T a join #T b on a.Name=b.Name and a.ID>=b.ID group by a.ID,a.Name,a.Memo having count(1)=1


方法5:
select * from #T a group by ID,Name,Memo having ID=(select min(ID)from #T where Name=a.Name)


方法6:
select * from #T a where (select count(1) from #T where Name=a.Name and ID<a.ID)=0


方法7:
select * from #T a where ID=(select top 1 ID from #T where Name=a.name order by ID)


方法8:
select * from #T a where ID!>all(select ID from #T where Name=a.Name)


方法9(注:ID为唯一时可用):
select * from #T a where ID in(select min(ID) from #T group by Name)


--SQL2005: www.52mvc.com


方法10:
select ID,Name,Memo from (select *,min(ID)over(partition by Name) as MinID from #T a)T where ID=MinID


方法11:


select ID,Name,Memo from (select *,row_number()over(partition by Name order by ID) as MinID from #T a)T where MinID=1


生成结果:
/*
ID Name Memo
----------- ---- ----
1 A A1
4 B B1


(2 行受影响)
*/


--II、Name相同ID最大的记录,与min相反:
方法1:
Select * from #T a where not exists(select 1 from #T where Name=a.Name and ID>a.ID)


方法2:
select a.* from #T a join (select max(ID)ID,Name from #T group by Name) b on a.Name=b.Name and a.ID=b.ID order by ID


方法3:
select * from #T a where ID=(select max(ID) from #T where Name=a.Name) order by ID


方法4:
select a.* from #T a join #T b on a.Name=b.Name and a.ID<=b.ID group by a.ID,a.Name,a.Memo having count(1)=1


方法5:
select * from #T a group by ID,Name,Memo having ID=(select max(ID)from #T where Name=a.Name)


方法6:
select * from #T a where (select count(1) from #T where Name=a.Name and ID>a.ID)=0


方法7:
select * from #T a where ID=(select top 1 ID from #T where Name=a.name order by ID desc)


方法8:
select * from #T a where ID!<all(select ID from #T where Name=a.Name)

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Tags:MSSQL 处理 重复

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