WEB开发网      濠靛倻鏅悵顖涚附閽樺鐎诲ù婊庡亾缁辨帗鎷呴悩鍨暠濞戞挴鍋撳ù鐘烘閸ㄥ孩绂嶉锝喰﹂柟瀛樺灣濠婃垿鎯冮崟顏嗩伇濞寸姾妫勬慨鈺呭礉濞戝磭骞㈤悹鍥у槻閸ㄥ孩绂嶉敓锟� ---闁挎洩鎷�
开发学院软件开发Delphi 跟日期有关的两条经典SQL语句 阅读

跟日期有关的两条经典SQL语句

 2006-02-04 13:54:31 来源:WEB开发网 闁靛棴鎷�闁告垵绻愰惃顒傗偓娑欍仦缂嶏拷濠⒀呭仜閵囧洨鈧稒銇炵紞锟�闁靛棴鎷�  闁稿繗娅曢弫鐐哄级閵婏缚鑸瀣仧濞堟垵顕ラ鐓庤Е
核心提示:1.用一条语句得出某日期所在月份的最大天数? SELECT DAY(DATEADD(dd, -DAY('2004-02-13'), DATEADD(mm, 1, '2004-02-13'))) AS 'Day Number'2.少记录变成多条记录问题有表tbl日期 收入
1.用一条语句得出某日期所在月份的最大天数?

SELECT DAY(DATEADD(dd, -DAY('2004-02-13'), DATEADD(mm, 1, '2004-02-13'))) AS 'Day Number'

2.少记录变成多条记录问题

有表tbl
  日期    收入   支出
  2004-02-11 00:00:00 60 45
  2004-03-01 00:00:00 60 45
  2004-03-02 00:00:00 40 50
  2004-03-05 00:00:00 50 40



  /*
  测试数据:
  Create Table tbl([日期] smalldatetime,[收入] int ,[支出] int)

Insert Into tbl
  SELECT '2004-02-11', 60, 45
  union SELECT '2004-03-01',60, 45
  union SELECT '2004-03-02',40, 50
  union SELECT '2004-03-05',50, 40
  */

要得到的结果:
  日期    收入   支出   余额
  2004-02-01 00:00:00 NULL NULL NULL
  2004-02-02 00:00:00 NULL NULL NULL
  2004-02-03 00:00:00 NULL NULL NULL
  2004-02-04 00:00:00 NULL NULL NULL
  2004-02-05 00:00:00 NULL NULL NULL
  2004-02-06 00:00:00 NULL NULL NULL
  2004-02-07 00:00:00 NULL NULL NULL
  2004-02-08 00:00:00 NULL NULL NULL
  2004-02-09 00:00:00 NULL NULL NULL
  2004-02-10 00:00:00 NULL NULL NULL
  2004-02-11 00:00:00 60 45 15
  2004-02-12 00:00:00 NULL NULL 15
  2004-02-13 00:00:00 NULL NULL 15
  2004-02-14 00:00:00 NULL NULL 15
  2004-02-15 00:00:00 NULL NULL 15
  2004-02-16 00:00:00 NULL NULL 15
  2004-02-17 00:00:00 NULL NULL 15
  2004-02-18 00:00:00 NULL NULL 15
  2004-02-19 00:00:00 NULL NULL 15
  2004-02-20 00:00:00 NULL NULL 15
  2004-02-21 00:00:00 NULL NULL 15
2004-02-22 00:00:00 NULL NULL 15
  2004-02-23 00:00:00 NULL NULL 15
  2004-02-24 00:00:00 NULL NULL 15
  2004-02-25 00:00:00 NULL NULL 15
  2004-02-26 00:00:00 NULL NULL 15
  2004-02-27 00:00:00 NULL NULL 15
  2004-02-28 00:00:00 NULL NULL 15
  2004-02-29 00:00:00 NULL NULL 15
  2004-03-01 00:00:00 60 45 30
  2004-03-02 00:00:00 40 50 20
  2004-03-03 00:00:00 NULL NULL 20
  2004-03-04 00:00:00 NULL NULL 20
  2004-03-05 00:00:00 50 40 30
  2004-03-06 00:00:00 NULL NULL 30
  2004-03-07 00:00:00 NULL NULL 30
  2004-03-08 00:00:00 NULL NULL 30
  2004-03-09 00:00:00 NULL NULL 30
  2004-03-10 00:00:00 NULL NULL 30
  2004-03-11 00:00:00 NULL NULL 30
  2004-03-12 00:00:00 NULL NULL 30
  2004-03-13 00:00:00 NULL NULL 30
  2004-03-14 00:00:00 NULL NULL 30
  2004-03-15 00:00:00 NULL NULL 30
  2004-03-16 00:00:00 NULL NULL 30
  2004-03-17 00:00:00 NULL NULL 30
  2004-03-18 00:00:00 NULL NULL 30
  2004-03-19 00:00:00 NULL NULL 30
  2004-03-20 00:00:00 NULL NULL 30
  2004-03-21 00:00:00 NULL NULL 30
  2004-03-22 00:00:00 NULL NULL 30
  2004-03-23 00:00:00 NULL NULL 30
  2004-03-24 00:00:00 NULL NULL 30
  2004-03-25 00:00:00 NULL NULL 30
  2004-03-26 00:00:00 NULL NULL 30
  2004-03-27 00:00:00 NULL NULL 30
  2004-03-28 00:00:00 NULL NULL 30
  2004-03-29 00:00:00 NULL NULL 30
  2004-03-30 00:00:00 NULL NULL 30
  2004-03-31 00:00:00 NULL NULL 30

答案:


  SELECT Y.[日期], tbl.[收入], tbl.[支出], (
  SELECT SUM(ISNULL(tbl.[收入], 0)-ISNULL(tbl.[支出], 0)) FROM tbl WHERE [日期]<=Y.[日期]) AS [余额]
  FROM tbl RIGHT JOIN (
  SELECT DATEADD(dd, N.i, DATEADD(dd, 1-DAY(m.MinDay), m.MinDay)) AS [日期]
  FROM (
  SELECT 0 AS i




  UNION ALL SELECT 1
  UNION ALL SELECT 2
  UNION ALL SELECT 3
  UNION ALL SELECT 4
  UNION ALL SELECT 5
  UNION ALL SELECT 6
  UNION ALL SELECT 7
  UNION ALL SELECT 8
  UNION ALL SELECT 9
  UNION ALL SELECT 10
  UNION ALL SELECT 11
  UNION ALL SELECT 12
  UNION ALL SELECT 13
  UNION ALL SELECT 14
  UNION ALL SELECT 15
  UNION ALL SELECT 16
  UNION ALL SELECT 17
  UNION ALL SELECT 18
  UNION ALL SELECT 19
  UNION ALL SELECT 20
  UNION ALL SELECT 21
  UNION ALL SELECT 22
  UNION ALL SELECT 23
  UNION ALL SELECT 24
  UNION ALL SELECT 25
  UNION ALL SELECT 26
  UNION ALL SELECT 27
  UNION ALL SELECT 28
  UNION ALL SELECT 29
  UNION ALL SELECT 30
  UNION ALL SELECT 31
  ) N,
  (
  SELECT MIN(日期) AS MinDay
  FROM tbl
  GROUP BY DATEDIFF(month, 0, 日期)
  ) M
  WHERE DATEDIFF(mm, DATEADD(dd, N.i, DATEADD(dd, 1-DAY(m.MinDay), m.MinDay)), M.MinDay)=0) AS Y
  ON tbl.[日期]=Y.日期

Tags:日期 有关 经典

编辑录入:爽爽 [复制链接] [打 印]
赞助商链接