Java编程获取硬盘空间
2008-01-05 19:17:06 来源:WEB开发网因为论坛有人问到这个问题,所以就写了这篇文章。希望对大家有所帮助。
一般来讲,要用java得到硬盘空间,有3种方法:
1. 调用system的command,然后分析得到的结果,这种方法有很强的系统依靠性,linux下和win下要分别写程序。
下面是一个win下的例子,编译成功之后,运行java Diskspace yourdir(比如c:\)
import java.io.BufferedReader;
import java.io.InputStreamReader;
/**
* Determine free disk space for a given Directory by
* parsing the output of the dir command.
* This class is inspired by the code at
* Works only under Windows under certain circumstances.
* Yes, it's that shaky.
* Requires Java 1.4 or higher.
* @[EMAIL PROTECTED]
*Marco Schmidt
*/
public class Diskspace
{
private Diskspace()
{
// prevent instantiation of this class
}
/**
* Return available free disk space for a directory.
* @[EMAIL PROTECTED]
dirName name of the directory
* @[EMAIL PROTECTED]
free disk space in bytes or -1 if unknown
*/
public static long getFreeDiskSpace(String dirName)
{
try
{
// guess correct 'dir' command by looking at the
// Operating system name
String os = System.getProperty("os.name");
String command;
if (os.equals("Windows NT") os.equals("windows 2000"))
{
command = "cmd.exe /c dir " + dirName;
}
else
{
command = "command.com /c dir " + dirName;
}
// run the dir command on the argument directory name
Runtime runtime = Runtime.getRuntime();
Process process = null;
process = runtime.exec(command);
if (process == null)
{
return -1;
}
// read the output of the dir command
// only the last line is of interest
BufferedReader in = new BufferedReader(new InputStreamReader(process.getInputStream()));
String line;
String freeSpace = null;
while ((line = in.readLine()) != null)
{
freeSpace = line;
}
if (freeSpace == null)
{
return -1;
}
process.destroy();
// remove dots & commas & leading and trailing whitespace
freeSpace = freeSpace.trim();
freeSpace = freeSpace.replaceAll("\\.", "");
freeSpace = freeSpace.replaceAll(",", "");
String[] items = freeSpace.split(" ");
// the first valid numeric value in items after(!) index 0
// is probably the free disk space
int index = 1;
while (index < items.length)
{
try
{
long bytes = Long.parseLong(items[index++]);
return bytes;
}
catch (NumberFormatException nfe)
{
}
}
return -1;
}
catch (Exception exception)
{
return -1;
}
}
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