开发学院WEB开发Jsp Test of the Java Skill(4) 阅读

Test of the Java Skill(4)

 2008-01-05 20:29:18 来源:WEB开发网   
核心提示: Question 25: What will happen when you attempt to compile and run the following code? int Output = 10; boolean b1 = false; if ((b1==true)&&((Output+=10)==2


   Question 25:
   What will happen when you attempt to compile and run the following code?

   int Output = 10;
   boolean b1 = false;
   if ((b1==true)&&((Output+=10)==20)){
   System.out.PRintln(“We are equal “ + Output);
   }
   else{
   System.out.println(“Not equal!” + Output);
   }

   A. Compile error, attempting to perform binary comparison on logical data type

   B. Compilation and output of “We are equal 10”

   C. Compilation and output of “Not equal! 20”

   D. Compilation and output of “Not equal! 10”

   Question 26:
   Which of the following are true?

   A. java uses a time-slicing scheduling system for determining which Thread will execute.

   B. Java uses a pre-emptive, co-Operative system for determining which Thread will execute.

   C. Java scheduling is platform dependent and may vary from one implementation to another.

   D. You can set the priority of a Thread in code.
  Question 27:
   What will happen when you attempt to compile and run the following code?

   public class MySwitch{
   public static void main(String argv[]){
   MySwitch ms = new MySwitch();
   ms.amethod();
   }
   public void amethod(){
   int k=10;
   switch(k){
   default:
   System.out.println(“This is the default output”);
   break;
   case 10:
   System.out.println(“ten”);
   case 20:
   System.out.println(“twenty”);
   break;
   }
   }
   }

   A. None of these options

   B. Compile time error target of switch must be an integral type

   C. Compile and run with output “This is the default output”

   D. Compile and run with output “ten”

   Question 28:
   What will happen when you attempt to compile and run the following code?
   public class StrEq{
   public static void main(String argv[]){
   StrEq s = new StrEq();
   }
   private StrEq(){
   String s = “Marcus”;
   String s2 = new String(“Marcus”);
   if (s==s2){
   System.out.println(“we have a match”);
   }else{
   System.out.println(“Not equal”);
   }
   }
   }

   A. Compile time error caused by private constrUCtor

   B. Output of “we have a match”

   C. Output of “Not equal”

   D. Compile time error by attempting to compare string using ==

Tags:Test of the

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