让数据库产生一张详细的日历表
2007-11-11 07:34:00 来源:WEB开发网核心提示:也许有了这张表,你的工作会轻松很多! CREATE TABLE [dbo].[time_dimension] ( [time_id] [int] IDENTITY (1, 1) NOT NULL , [the_date] [datetime] NULL , [the_day] [nvarchar] (15) NU
也许有了这张表,你的工作会轻松很多!
CREATE TABLE [dbo].[time_dimension] (
[time_id] [int] IDENTITY (1, 1) NOT NULL ,
[the_date] [datetime] NULL ,
[the_day] [nvarchar] (15) NULL ,
[the_month] [nvarchar] (15) NULL ,
[the_year] [smallint] NULL ,
[day_of_month] [smallint] NULL ,
[week_of_year] [smallint] NULL ,
[month_of_year] [smallint] NULL ,
[quarter] [nvarchar] (2) NULL ,
[fiscal_period] [nvarchar] (20) NULL
) ON [Prima(最完善的虚拟主机管理系统)RY]
DECLARE @WeekString varchar(12),
@dDate SMALLDATETIME,
@sMonth varchar(20),
@iYear smallint,
@iDayOfMonth smallint,
@iWeekOfYear smallint,
@iMonthOfYear smallint,
@sQuarter varchar(2),
@sSQL varchar(100),
@adddays int
SELECT @adddays = 1 --日期增量(可以自由设定)
SELECT @dDate = ’01/01/2002’ --开始日期
WHILE @dDate < ’12/31/2004’ --结束日期
BEGIN
SELECT @WeekString = DATENAME (dw, @dDate)
SELECT @sMonth=DATENAME(mm,@dDate)
SELECT @iYear= DATENAME (yy, @dDate)
SELECT @iDayOfMonth=DATENAME (dd, @dDate)
SELECT @iWeekOfYear= DATENAME (week, @dDate)
SELECT @iMonthOfYear=DATEPART(month, @dDate)
SELECT @sQuarter = ’Q’ + CAST(DATENAME (quarter, @dDate)as varchar(1))
INSERT INTO time_dimension(the_date, the_day, the_month, the_year,
day_of_month,
week_of_year, month_of_year, quarter) VALUES
(@dDate, @WeekString, @sMonth, @iYear, @iDayOfMonth, @iWeekOfYear,
@iMonthOfYear, @sQuarter)
SELECT @dDate = @dDate + @adddays
END
GO
select * from time_dimension
更多精彩
赞助商链接