详解Android 开发中的Content Provider
2010-02-03 16:09:00 来源:WEB开发网}
}
上面的类中定义了Content Provider的CONTENT_URI,以及数据列。下面我们将定义基于上面的类来定义实际的Content Provider类:
package com.wissen.testApp.android;
public class MyContentProvider extends ContentProvider {
private SQLiteDatabase sqlDB;
private DatabaseHelper dbHelper;
private static final String DATABASE_NAME = “Users.db”;
private static final int DATABASE_VERSION = 1;
private static final String TABLE_NAME = “User”;
private static final String TAG = “MyContentProvider”;
private static class DatabaseHelper extends SQLiteOpenHelper {
DatabaseHelper(Context context) {
super(context, DATABASE_NAME, null, DATABASE_VERSION);
}
@Override
public void onCreate(SQLiteDatabase db) {
//创建用于存储数据的表
db.execSQL(”Create table ” + TABLE_NAME + “( _id INTEGER PRIMARY KEY AUTOINCREMENT, USER_NAME TEXT);”);
}
@Override
public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) {
db.execSQL(”DROP TABLE IF EXISTS ” + TABLE_NAME);
onCreate(db);
}
}
@Override
public int delete(Uri uri, String s, String[] as) {
return 0;
}
@Override
public String getType(Uri uri) {
return null;
}
@Override
public Uri insert(Uri uri, ContentValues contentvalues) {
sqlDB = dbHelper.getWritableDatabase();
long rowId = sqlDB.insert(TABLE_NAME, “”, contentvalues);
if (rowId > 0) {
Uri rowUri = ContentUris.appendId(MyUsers.User.CONTENT_URI.buildUpon(), rowId).build();
getContext().getContentResolver().notifyChange(rowUri, null);
return rowUri;
}
throw new SQLException(”Failed to insert row into ” + uri);
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