C#中只接受数字输入的控件
2009-06-04 08:30:14 来源:WEB开发网 閵嗭拷

核心提示: 运行程序,在输入任意非0-9的字符时的样子: (截图反映的是在我的简体中文Windows XP上的运行效果;若系统语言不是简体中文的话会根据系统语言而不同) 如果这个文本框已经能满足需求,C#中只接受数字输入的控件(3),就没必要自己监听KeyDown事件那么麻烦了, 二、自行监听KeyD
运行程序,在输入任意非0-9的字符时的样子:
(截图反映的是在我的简体中文Windows XP上的运行效果;若系统语言不是简体中文的话会根据系统语言而不同)
如果这个文本框已经能满足需求,就没必要自己监听KeyDown事件那么麻烦了。
二、自行监听KeyDown事件
可以参考CodeProject上Numeric TextBox : Allow your users to enter numeric data the easy way的实现方式。基本原理就是在KeyDown的响应方法中对e.KeyCode进行判断,如果输入不满足条件则设置某个标识,然后再KeyPress的响应方法里设置e.Handled = true;来取消该次事件。
最简单来说类似这样:
C#代码
using System; using System.Drawing; using System.Windows.Forms; sealed class TestForm : Form { private TextBox m_textBox; private bool m_nonNumberEntered = false; public TestForm() { InitializeComponent(); } private void InitializeComponent() { this.m_textBox = new TextBox(); this.m_textBox.Dock = DockStyle.Fill; this.m_textBox.KeyDown += m_textBox_KeyDown; this.m_textBox.KeyPress += m_textBox_KeyPress; this.ClientSize = new Size(100, 60); this.Controls.Add(this.m_textBox); this.PerformLayout(); } private void m_textBox_KeyDown(object sender, KeyEventArgs e) { // Initialize the flag to false. m_nonNumberEntered = false; // Determine whether the keystroke is a number from the top of the keyboard. if (e.KeyCode < Keys.D0 || e.KeyCode > Keys.D9) { // Determine whether the keystroke is a number from the keypad. if (e.KeyCode < Keys.NumPad0 || e.KeyCode > Keys.NumPad9) { // Determine whether the keystroke is a backspace. if(e.KeyCode != Keys.Back) { // A non-numerical keystroke was pressed. // Set the flag to true and evaluate in KeyPress event. m_nonNumberEntered = true; } } } } private void m_textBox_KeyPress(object sender, KeyPressEventArgs e) { // Check for the flag being set in the KeyDown event. if (m_nonNumberEntered) { // Stop the character from being entered into the control // since it is non-numerical. e.Handled = true; } } [STAThread] static void Main(string[] args) { Application.EnableVisualStyles(); Application.SetCompatibleTextRenderingDefault(false); Application.Run(new TestForm()); } }
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